What are the solutions to the equation x^2-12x+36=9 ?

The solutions to the equation x^2-12x+36=9 are x=9,x=3

Find the zeros of x^2-12x+36=9

The zeros of x^2-12x+36=9 are x=9,x=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 12 x + 36 = 9

x = 9, x = 3

Solution steps

x^{2} - 12 x + 36 = 9

Move

9

to the left side

x^{2} - 12 x + 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 27}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 27 = 6

x_{1, 2} = \frac{- ( - 12 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 6}{2 \cdot 1}

x = \frac{- ( - 12 ) + 6}{2 \cdot 1} : 9

x = \frac{- ( - 12 ) - 6}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 9, x = 3

x, f = x^{2} + x y^{2} - z^{2}

- (x - 7)^{2} = - 17

x^{2} - x - 6 = - 6 - 7 x

- x^{2} + 4 x - 8 = 0

x, x^{2} - 4 x y + y^{2} = 4

What are the solutions to the equation x^2-12x+36=9 ?
The solutions to the equation x^2-12x+36=9 are x=9,x=3
Find the zeros of x^2-12x+36=9
The zeros of x^2-12x+36=9 are x=9,x=3