What is factor x^6+7x^3-8 ?

The solution to factor x^6+7x^3-8 is (x-1)(x^2+x+1)(x+2)(x^2-2x+4)

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factor x^6+7x^3-8

factor

x^{6} + 7 x^{3} - 8

(x - 1) (x^{2} + x + 1) (x + 2) (x^{2} - 2 x + 4)

Solution steps

x^{6} + 7 x^{3} - 8

Use the rational root theorem

= (x - 1) \frac{x ^{6} + 7 x ^{3} - 8}{x - 1}

\frac{x ^{6} + 7 x ^{3} - 8}{x - 1} = x^{5} + x^{4} + x^{3} + 8 x^{2} + 8 x + 8

= (x - 1) (x^{5} + x^{4} + x^{3} + 8 x^{2} + 8 x + 8)

Factor

x^{5} + x^{4} + x^{3} + 8 x^{2} + 8 x + 8 : (x^{2} + x + 1) (x + 2) (x^{2} - 2 x + 2^{2})

= (x - 1) (x^{2} + x + 1) (x + 2) (x^{2} - 2 x + 2^{2})

2^{2} = 4

= (x - 1) (x^{2} + x + 1) (x + 2) (x^{2} - 2 x + 4)

- 5 x - 9 < 11

5^{2} \cdot 5^{- 6}

\frac{5 ^{2}}{5 ^{8}}

8 (- 3) - 2 (- 6) \geq - 12

50 - 2

What is factor x^6+7x^3-8 ?
The solution to factor x^6+7x^3-8 is (x-1)(x^2+x+1)(x+2)(x^2-2x+4)