What are the solutions to the equation 5(x+2)^2=-125 ?

The solutions to the equation 5(x+2)^2=-125 are x=5i-2,x=-5i-2

Find the zeros of 5(x+2)^2=-125

The zeros of 5(x+2)^2=-125 are x=5i-2,x=-5i-2

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5 (x + 2)^{2} = - 125

x = 5 i - 2, x = - 5 i - 2

Solution steps

5 (x + 2)^{2} = - 125

Divide both sides by

5

(x + 2)^{2} = - 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = - 25 : x = 5 i - 2

Solve

x + 2 = - - 25 : x = - 5 i - 2

The solutions to the quadratic equation are:

x = 5 i - 2, x = - 5 i - 2

(a + 5) x^{2} + 1 = (a + 2) x

12 x^{2} - 104 x + 160 = 0

x^{2} - 84 = 2 x - 4

y, 2 x^{2} + x y + y^{2} = 4

2 w^{2} + 9 w - 10 = 6 w

What are the solutions to the equation 5(x+2)^2=-125 ?
The solutions to the equation 5(x+2)^2=-125 are x=5i-2,x=-5i-2
Find the zeros of 5(x+2)^2=-125
The zeros of 5(x+2)^2=-125 are x=5i-2,x=-5i-2