What are the solutions to the equation 6x^2-36x+72=0 ?

The solutions to the equation 6x^2-36x+72=0 are x=3+sqrt(3)i,x=3-sqrt(3)i

Find the zeros of 6x^2-36x+72=0

The zeros of 6x^2-36x+72=0 are x=3+sqrt(3)i,x=3-sqrt(3)i

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6 x^{2} - 36 x + 72 = 0

x = 3 + 3 i, x = 3 - 3 i

Solution steps

6 x^{2} - 36 x + 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 6 \cdot 72}{2 \cdot 6}

Simplify

(- 36)^{2} - 4 \cdot 6 \cdot 72 : 123 i

x_{1, 2} = \frac{- ( - 36 ) \pm 12 3 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 12 3 i}{2 \cdot 6}, x_{2} = \frac{- ( - 36 ) - 12 3 i}{2 \cdot 6}

x = \frac{- ( - 36 ) + 12 3 i}{2 \cdot 6} : 3 + 3 i

x = \frac{- ( - 36 ) - 12 3 i}{2 \cdot 6} : 3 - 3 i

The solutions to the quadratic equation are:

x = 3 + 3 i, x = 3 - 3 i

(q + \frac{5}{4})^{2} + 7 = - 18

x^{2} + 20 x + 100 = 64

0 = x^{2} - 8 x + 12

- w^{2} + 5 w - 4 = 0

x^{2} + 2 x = x + 2

What are the solutions to the equation 6x^2-36x+72=0 ?
The solutions to the equation 6x^2-36x+72=0 are x=3+sqrt(3)i,x=3-sqrt(3)i
Find the zeros of 6x^2-36x+72=0
The zeros of 6x^2-36x+72=0 are x=3+sqrt(3)i,x=3-sqrt(3)i