What are the solutions to the equation k^2+k-21=-3 ?

The solutions to the equation k^2+k-21=-3 are k=(-1+sqrt(73))/2 ,k=(-1-sqrt(73))/2

Find the zeros of k^2+k-21=-3

The zeros of k^2+k-21=-3 are k=(-1+sqrt(73))/2 ,k=(-1-sqrt(73))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

k^{2} + k - 21 = - 3

k = \frac{- 1 + 73}{2}, k = \frac{- 1 - 73}{2}

Decimal Notation

k = 3.77200 \dots, k = - 4.77200 \dots

Solution steps

k^{2} + k - 21 = - 3

Move

3

to the left side

k^{2} + k - 18 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 18) = 73

k_{1, 2} = \frac{- 1 \pm 73}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- 1 + 73}{2 \cdot 1}, k_{2} = \frac{- 1 - 73}{2 \cdot 1}

k = \frac{- 1 + 73}{2 \cdot 1} : \frac{- 1 + 73}{2}

k = \frac{- 1 - 73}{2 \cdot 1} : \frac{- 1 - 73}{2}

The solutions to the quadratic equation are:

k = \frac{- 1 + 73}{2}, k = \frac{- 1 - 73}{2}

x^{2} + 4 x + 1

4 x^{2} - 40 x + 64 = 0

(x - 11)^{2} = 36

- x^{2} + 3 x + 40 = 0

5 x^{2} + 38 = 3

What are the solutions to the equation k^2+k-21=-3 ?
The solutions to the equation k^2+k-21=-3 are k=(-1+sqrt(73))/2 ,k=(-1-sqrt(73))/2
Find the zeros of k^2+k-21=-3
The zeros of k^2+k-21=-3 are k=(-1+sqrt(73))/2 ,k=(-1-sqrt(73))/2