What are the solutions to the equation 11x^2-9x+1=6x^2 ?

The solutions to the equation 11x^2-9x+1=6x^2 are x=(9+sqrt(61))/(10),x=(9-sqrt(61))/(10)

Find the zeros of 11x^2-9x+1=6x^2

The zeros of 11x^2-9x+1=6x^2 are x=(9+sqrt(61))/(10),x=(9-sqrt(61))/(10)

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11 x^{2} - 9 x + 1 = 6 x^{2}

x = \frac{9 + 61}{10}, x = \frac{9 - 61}{10}

Decimal Notation

x = 1.68102 \dots, x = 0.11897 \dots

Solution steps

11 x^{2} - 9 x + 1 = 6 x^{2}

Move

6 x^{2}

to the left side

5 x^{2} - 9 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 5 \cdot 1}{2 \cdot 5}

(- 9)^{2} - 4 \cdot 5 \cdot 1 = 61

x_{1, 2} = \frac{- ( - 9 ) \pm 61}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 61}{2 \cdot 5}, x_{2} = \frac{- ( - 9 ) - 61}{2 \cdot 5}

x = \frac{- ( - 9 ) + 61}{2 \cdot 5} : \frac{9 + 61}{10}

x = \frac{- ( - 9 ) - 61}{2 \cdot 5} : \frac{9 - 61}{10}

The solutions to the quadratic equation are:

x = \frac{9 + 61}{10}, x = \frac{9 - 61}{10}

x^{2} + 16 x - 2 = 11

2 (4 x - 10)^{2} = 26

x^{2} + 98 = 8 x + 7

x^{2} + 18 x + 45 = 0

5 x^{2} = - 3 x

What are the solutions to the equation 11x^2-9x+1=6x^2 ?
The solutions to the equation 11x^2-9x+1=6x^2 are x=(9+sqrt(61))/(10),x=(9-sqrt(61))/(10)
Find the zeros of 11x^2-9x+1=6x^2
The zeros of 11x^2-9x+1=6x^2 are x=(9+sqrt(61))/(10),x=(9-sqrt(61))/(10)