What are the solutions to the equation 2x^2-8x+10=0 ?

The solutions to the equation 2x^2-8x+10=0 are x=2+i,x=2-i

Find the zeros of 2x^2-8x+10=0

The zeros of 2x^2-8x+10=0 are x=2+i,x=2-i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 8 x + 10 = 0

x = 2 + i, x = 2 - i

Solution steps

2 x^{2} - 8 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 \cdot 10}{2 \cdot 2}

Simplify

(- 8)^{2} - 4 \cdot 2 \cdot 10 : 4 i

x_{1, 2} = \frac{- ( - 8 ) \pm 4 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 i}{2 \cdot 2}, x_{2} = \frac{- ( - 8 ) - 4 i}{2 \cdot 2}

x = \frac{- ( - 8 ) + 4 i}{2 \cdot 2} : 2 + i

x = \frac{- ( - 8 ) - 4 i}{2 \cdot 2} : 2 - i

The solutions to the quadratic equation are:

x = 2 + i, x = 2 - i

(x + \frac{1}{3}) (x - \frac{1}{3}) = \frac{1}{3}

x^{2} + 6 x = - x + 30

0 = 3 x^{2} + 6 x

x^{2} - 10 x + 2 = 0

(x - 3)^{2} + x (x + 2) = 9

What are the solutions to the equation 2x^2-8x+10=0 ?
The solutions to the equation 2x^2-8x+10=0 are x=2+i,x=2-i
Find the zeros of 2x^2-8x+10=0
The zeros of 2x^2-8x+10=0 are x=2+i,x=2-i