What are the solutions to the equation x^2+11x+11=4x ?

The solutions to the equation x^2+11x+11=4x are x=(-7+sqrt(5))/2 ,x=(-7-sqrt(5))/2

Find the zeros of x^2+11x+11=4x

The zeros of x^2+11x+11=4x are x=(-7+sqrt(5))/2 ,x=(-7-sqrt(5))/2

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x^{2} + 11 x + 11 = 4 x

x = \frac{- 7 + 5}{2}, x = \frac{- 7 - 5}{2}

Decimal Notation

x = - 2.38196 \dots, x = - 4.61803 \dots

Solution steps

x^{2} + 11 x + 11 = 4 x

Move

4 x

to the left side

x^{2} + 7 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 11}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 11 = 5

x_{1, 2} = \frac{- 7 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 5}{2 \cdot 1}, x_{2} = \frac{- 7 - 5}{2 \cdot 1}

x = \frac{- 7 + 5}{2 \cdot 1} : \frac{- 7 + 5}{2}

x = \frac{- 7 - 5}{2 \cdot 1} : \frac{- 7 - 5}{2}

The solutions to the quadratic equation are:

x = \frac{- 7 + 5}{2}, x = \frac{- 7 - 5}{2}

x^{2} - 5 x = 0

x - 36 = x^{2} - 11 x

3 x^{2} + 1 = 5

x^{2} + 5 = 30

3 x^{2} + 2 x - 21 = 0

What are the solutions to the equation x^2+11x+11=4x ?
The solutions to the equation x^2+11x+11=4x are x=(-7+sqrt(5))/2 ,x=(-7-sqrt(5))/2
Find the zeros of x^2+11x+11=4x
The zeros of x^2+11x+11=4x are x=(-7+sqrt(5))/2 ,x=(-7-sqrt(5))/2