What are the solutions to the equation x^2+x-3/4 =0 ?

The solutions to the equation x^2+x-3/4 =0 are x= 1/2 ,x=-3/2

Find the zeros of x^2+x-3/4 =0

The zeros of x^2+x-3/4 =0 are x= 1/2 ,x=-3/2

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x^{2} + x - \frac{3}{4} = 0

x = \frac{1}{2}, x = - \frac{3}{2}

Decimal Notation

x = 0.5, x = - 1.5

Solution steps

x^{2} + x - \frac{3}{4} = 0

Multiply both sides by

4

4 x^{2} + 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

4^{2} - 4 \cdot 4 (- 3) = 8

x_{1, 2} = \frac{- 4 \pm 8}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 4 + 8}{2 \cdot 4}, x_{2} = \frac{- 4 - 8}{2 \cdot 4}

x = \frac{- 4 + 8}{2 \cdot 4} : \frac{1}{2}

x = \frac{- 4 - 8}{2 \cdot 4} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{3}{2}

f, h = f (g + f)

3 x (x - 2) = 0

x^{2} + 8 x = 12

x^{2} + 20 x + 100 = 144

2 x^{2} - 4 x

What are the solutions to the equation x^2+x-3/4 =0 ?
The solutions to the equation x^2+x-3/4 =0 are x= 1/2 ,x=-3/2
Find the zeros of x^2+x-3/4 =0
The zeros of x^2+x-3/4 =0 are x= 1/2 ,x=-3/2