What are the solutions to the equation (x-1/4)(x+1/4)= 3/16 ?

The solutions to the equation (x-1/4)(x+1/4)= 3/16 are x= 1/2 ,x=-1/2

Find the zeros of (x-1/4)(x+1/4)= 3/16

The zeros of (x-1/4)(x+1/4)= 3/16 are x= 1/2 ,x=-1/2

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(x - \frac{1}{4}) (x + \frac{1}{4}) = \frac{3}{16}

x = \frac{1}{2}, x = - \frac{1}{2}

Decimal Notation

x = 0.5, x = - 0.5

Solution steps

(x - \frac{1}{4}) (x + \frac{1}{4}) = \frac{3}{16}

Multiply both sides by

16

16 (x - \frac{1}{4}) (x + \frac{1}{4}) = 3

Expand

16 (x - \frac{1}{4}) (x + \frac{1}{4}) : 16 x^{2} - 1

16 x^{2} - 1 = 3

Move

3

to the left side

16 x^{2} - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 16 ( - 4 )}{2 \cdot 16}

0^{2} - 4 \cdot 16 (- 4) = 16

x_{1, 2} = \frac{- 0 \pm 16}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- 0 + 16}{2 \cdot 16}, x_{2} = \frac{- 0 - 16}{2 \cdot 16}

x = \frac{- 0 + 16}{2 \cdot 16} : \frac{1}{2}

x = \frac{- 0 - 16}{2 \cdot 16} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{1}{2}

5 x - x^{2} = 2 x - 2

w^{2} - 8 w + 7 = - 3

x^{2} - 13 x - 11 = - 7 x + 5

6 x^{2} + 19 x + 10 = 0

4 - 12 x^{2} = 0

What are the solutions to the equation (x-1/4)(x+1/4)= 3/16 ?
The solutions to the equation (x-1/4)(x+1/4)= 3/16 are x= 1/2 ,x=-1/2
Find the zeros of (x-1/4)(x+1/4)= 3/16
The zeros of (x-1/4)(x+1/4)= 3/16 are x= 1/2 ,x=-1/2