What are the solutions to the equation 1.5x^2+2x=0 ?

The solutions to the equation 1.5x^2+2x=0 are x=0,x=-4/3

Find the zeros of 1.5x^2+2x=0

The zeros of 1.5x^2+2x=0 are x=0,x=-4/3

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1.5 x^{2} + 2 x = 0

x = 0, x = - \frac{4}{3}

Decimal Notation

x = 0, x = - 1.33333 \dots

Solution steps

1.5 x^{2} + 2 x = 0

Multiply both sides by

10

15 x^{2} + 20 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 15 \cdot 0}{2 \cdot 15}

2 0^{2} - 4 \cdot 15 \cdot 0 = 20

x_{1, 2} = \frac{- 20 \pm 20}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- 20 + 20}{2 \cdot 15}, x_{2} = \frac{- 20 - 20}{2 \cdot 15}

x = \frac{- 20 + 20}{2 \cdot 15} : 0

x = \frac{- 20 - 20}{2 \cdot 15} : - \frac{4}{3}

The solutions to the quadratic equation are:

x = 0, x = - \frac{4}{3}

y, x^{2} + (y - x^{\frac{2}{3}})^{2} = 1

- 2 x^{2} + 4 x - 2 = 0

x^{2} = - 225

t^{2} + 8 t + 16 = 0

3 x^{2} + 6 x

What are the solutions to the equation 1.5x^2+2x=0 ?
The solutions to the equation 1.5x^2+2x=0 are x=0,x=-4/3
Find the zeros of 1.5x^2+2x=0
The zeros of 1.5x^2+2x=0 are x=0,x=-4/3