What are the solutions to the equation 3x^2-40x+100=0 ?

The solutions to the equation 3x^2-40x+100=0 are x=10,x= 10/3

Find the zeros of 3x^2-40x+100=0

The zeros of 3x^2-40x+100=0 are x=10,x= 10/3

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3 x^{2} - 40 x + 100 = 0

x = 10, x = \frac{10}{3}

Decimal Notation

x = 10, x = 3.33333 \dots

Solution steps

3 x^{2} - 40 x + 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 3 \cdot 100}{2 \cdot 3}

(- 40)^{2} - 4 \cdot 3 \cdot 100 = 20

x_{1, 2} = \frac{- ( - 40 ) \pm 20}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 40 ) + 20}{2 \cdot 3}, x_{2} = \frac{- ( - 40 ) - 20}{2 \cdot 3}

x = \frac{- ( - 40 ) + 20}{2 \cdot 3} : 10

x = \frac{- ( - 40 ) - 20}{2 \cdot 3} : \frac{10}{3}

The solutions to the quadratic equation are:

x = 10, x = \frac{10}{3}

x^{2} + x - 1

x^{2} - 24 x

x^{2} - 12 x = 85

x^{2} - 12 x + 32 = 4

x^{2} - 18 x = - 117

What are the solutions to the equation 3x^2-40x+100=0 ?
The solutions to the equation 3x^2-40x+100=0 are x=10,x= 10/3
Find the zeros of 3x^2-40x+100=0
The zeros of 3x^2-40x+100=0 are x=10,x= 10/3