What are the solutions to the equation 4x^2-16x+10=0 ?

The solutions to the equation 4x^2-16x+10=0 are x=(4+sqrt(6))/2 ,x=(4-sqrt(6))/2

Find the zeros of 4x^2-16x+10=0

The zeros of 4x^2-16x+10=0 are x=(4+sqrt(6))/2 ,x=(4-sqrt(6))/2

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4 x^{2} - 16 x + 10 = 0

x = \frac{4 + 6}{2}, x = \frac{4 - 6}{2}

Decimal Notation

x = 3.22474 \dots, x = 0.77525 \dots

Solution steps

4 x^{2} - 16 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 4 \cdot 10}{2 \cdot 4}

(- 16)^{2} - 4 \cdot 4 \cdot 10 = 46

x_{1, 2} = \frac{- ( - 16 ) \pm 4 6}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4 6}{2 \cdot 4}, x_{2} = \frac{- ( - 16 ) - 4 6}{2 \cdot 4}

x = \frac{- ( - 16 ) + 4 6}{2 \cdot 4} : \frac{4 + 6}{2}

x = \frac{- ( - 16 ) - 4 6}{2 \cdot 4} : \frac{4 - 6}{2}

The solutions to the quadratic equation are:

x = \frac{4 + 6}{2}, x = \frac{4 - 6}{2}

\frac{x ^{3}}{x ^{2}}

\frac{x}{3} - 8 = - 2

∣ 2 x + 5 ∣ \geq ∣ x + 4 ∣

\frac{1}{n ^{3}} \cdot \frac{( n - 1 ) ( 2 n - 1 )}{6}

3 ∣ 7 x ∣ + 5 = 29

What are the solutions to the equation 4x^2-16x+10=0 ?
The solutions to the equation 4x^2-16x+10=0 are x=(4+sqrt(6))/2 ,x=(4-sqrt(6))/2
Find the zeros of 4x^2-16x+10=0
The zeros of 4x^2-16x+10=0 are x=(4+sqrt(6))/2 ,x=(4-sqrt(6))/2