What are the solutions to the equation x^2+32=21 ?

The solutions to the equation x^2+32=21 are x=sqrt(11)i,x=-sqrt(11)i

Find the zeros of x^2+32=21

The zeros of x^2+32=21 are x=sqrt(11)i,x=-sqrt(11)i

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x^{2} + 32 = 21

x = 11 i, x = - 11 i

Solution steps

x^{2} + 32 = 21

Move

32

to the right side

x^{2} = - 11

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 11, x = - - 11

- 11 = 11 i

- - 11 = - 11 i

x = 11 i, x = - 11 i

2 + 4 + 6 + 2 n = n (n + 1)

x^{2} + 3 = 12

x^{2} + 7 x

3 x^{2} - 9 x - 54 = 0

m^{2} - 7 m + 12 = 0

What are the solutions to the equation x^2+32=21 ?
The solutions to the equation x^2+32=21 are x=sqrt(11)i,x=-sqrt(11)i
Find the zeros of x^2+32=21
The zeros of x^2+32=21 are x=sqrt(11)i,x=-sqrt(11)i