What are the solutions to the equation (3x+1)^2=9 ?

The solutions to the equation (3x+1)^2=9 are x= 2/3 ,x=-4/3

Find the zeros of (3x+1)^2=9

The zeros of (3x+1)^2=9 are x= 2/3 ,x=-4/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(3 x + 1)^{2} = 9

x = \frac{2}{3}, x = - \frac{4}{3}

Decimal Notation

x = 0.66666 \dots, x = - 1.33333 \dots

Solution steps

(3 x + 1)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 1 = 9 : x = \frac{2}{3}

Solve

3 x + 1 = - 9 : x = - \frac{4}{3}

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - \frac{4}{3}

x^{2} + 245 = 0

5 x^{2} + 8 x + 2

x^{2} = (x - 2) (x - 2 + x - 1)

3 x^{2} - 2 x - 21 = 0

r, s = 4 π r^{2}

What are the solutions to the equation (3x+1)^2=9 ?
The solutions to the equation (3x+1)^2=9 are x= 2/3 ,x=-4/3
Find the zeros of (3x+1)^2=9
The zeros of (3x+1)^2=9 are x= 2/3 ,x=-4/3