What are the solutions to the equation 4x^2-121=0 ?

The solutions to the equation 4x^2-121=0 are x= 11/2 ,x=-11/2

Find the zeros of 4x^2-121=0

The zeros of 4x^2-121=0 are x= 11/2 ,x=-11/2

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4 x^{2} - 121 = 0

x = \frac{11}{2}, x = - \frac{11}{2}

Decimal Notation

x = 5.5, x = - 5.5

Solution steps

4 x^{2} - 121 = 0

Move

121

to the right side

4 x^{2} = 121

Divide both sides by

4

x^{2} = \frac{121}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{121}{4}, x = - \frac{121}{4}

\frac{121}{4} = \frac{11}{2}

- \frac{121}{4} = - \frac{11}{2}

x = \frac{11}{2}, x = - \frac{11}{2}

x^{2} - 4 x + 3

2 (x + 5)^{2} + 37 = 39

12 + (x - 3)^{2} = - 24

(x - 17)^{2} = 1

s^{2} - 2 s + 2

What are the solutions to the equation 4x^2-121=0 ?
The solutions to the equation 4x^2-121=0 are x= 11/2 ,x=-11/2
Find the zeros of 4x^2-121=0
The zeros of 4x^2-121=0 are x= 11/2 ,x=-11/2