What are the solutions to the equation 7x^2-3x-4=0 ?

The solutions to the equation 7x^2-3x-4=0 are x=1,x=-4/7

Find the zeros of 7x^2-3x-4=0

The zeros of 7x^2-3x-4=0 are x=1,x=-4/7

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7 x^{2} - 3 x - 4 = 0

x = 1, x = - \frac{4}{7}

Decimal Notation

x = 1, x = - 0.57142 \dots

Solution steps

7 x^{2} - 3 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 7 ( - 4 )}{2 \cdot 7}

(- 3)^{2} - 4 \cdot 7 (- 4) = 11

x_{1, 2} = \frac{- ( - 3 ) \pm 11}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 11}{2 \cdot 7}, x_{2} = \frac{- ( - 3 ) - 11}{2 \cdot 7}

x = \frac{- ( - 3 ) + 11}{2 \cdot 7} : 1

x = \frac{- ( - 3 ) - 11}{2 \cdot 7} : - \frac{4}{7}

The solutions to the quadratic equation are:

x = 1, x = - \frac{4}{7}

2 x^{2} - 4 x - 16 = 0

(x - 4)^{2} = - 49

x^{2} = 3 x - 10

- 0.002 x^{2} + 0.37 x - 8 = 0

x, y = x^{2} - 5 x + 6

What are the solutions to the equation 7x^2-3x-4=0 ?
The solutions to the equation 7x^2-3x-4=0 are x=1,x=-4/7
Find the zeros of 7x^2-3x-4=0
The zeros of 7x^2-3x-4=0 are x=1,x=-4/7