What are the solutions to the equation 3b^2+18b+17=b ?

The solutions to the equation 3b^2+18b+17=b are b=(-17+sqrt(85))/6 ,b=(-17-sqrt(85))/6

Find the zeros of 3b^2+18b+17=b

The zeros of 3b^2+18b+17=b are b=(-17+sqrt(85))/6 ,b=(-17-sqrt(85))/6

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3 b^{2} + 18 b + 17 = b

b = \frac{- 17 + 85}{6}, b = \frac{- 17 - 85}{6}

Decimal Notation

b = - 1.29674 \dots, b = - 4.36992 \dots

Solution steps

3 b^{2} + 18 b + 17 = b

Move

b

to the left side

3 b^{2} + 17 b + 17 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 3 \cdot 17}{2 \cdot 3}

1 7^{2} - 4 \cdot 3 \cdot 17 = 85

b_{1, 2} = \frac{- 17 \pm 85}{2 \cdot 3}

Separate the solutions

b_{1} = \frac{- 17 + 85}{2 \cdot 3}, b_{2} = \frac{- 17 - 85}{2 \cdot 3}

b = \frac{- 17 + 85}{2 \cdot 3} : \frac{- 17 + 85}{6}

b = \frac{- 17 - 85}{2 \cdot 3} : \frac{- 17 - 85}{6}

The solutions to the quadratic equation are:

b = \frac{- 17 + 85}{6}, b = \frac{- 17 - 85}{6}

- 4 x^{2} + 64 x + 256 = 0

12 = x^{2}

x (2 x - 3) = 14

2 x^{2} = 1 - 2 x

8 x^{2} + 30 x = 2 x

What are the solutions to the equation 3b^2+18b+17=b ?
The solutions to the equation 3b^2+18b+17=b are b=(-17+sqrt(85))/6 ,b=(-17-sqrt(85))/6
Find the zeros of 3b^2+18b+17=b
The zeros of 3b^2+18b+17=b are b=(-17+sqrt(85))/6 ,b=(-17-sqrt(85))/6