What are the solutions to the equation 3(x+1)-x(5x+2)=7 ?

The solutions to the equation 3(x+1)-x(5x+2)=7 are x= 1/10-i(sqrt(79))/(10),x= 1/10+i(sqrt(79))/(10)

Find the zeros of 3(x+1)-x(5x+2)=7

The zeros of 3(x+1)-x(5x+2)=7 are x= 1/10-i(sqrt(79))/(10),x= 1/10+i(sqrt(79))/(10)

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3 (x + 1) - x (5 x + 2) = 7

x = \frac{1}{10} - i \frac{79}{10}, x = \frac{1}{10} + i \frac{79}{10}

Solution steps

3 (x + 1) - x (5 x + 2) = 7

Expand

3 (x + 1) - x (5 x + 2) : - 5 x^{2} + x + 3

- 5 x^{2} + x + 3 = 7

Move

7

to the left side

- 5 x^{2} + x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 5 ) ( - 4 )}{2 ( - 5 )}

Simplify

1^{2} - 4 (- 5) (- 4) : 79 i

x_{1, 2} = \frac{- 1 \pm 79 i}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 1 + 79 i}{2 ( - 5 )}, x_{2} = \frac{- 1 - 79 i}{2 ( - 5 )}

x = \frac{- 1 + 79 i}{2 ( - 5 )} : \frac{1}{10} - i \frac{79}{10}

x = \frac{- 1 - 79 i}{2 ( - 5 )} : \frac{1}{10} + i \frac{79}{10}

The solutions to the quadratic equation are:

x = \frac{1}{10} - i \frac{79}{10}, x = \frac{1}{10} + i \frac{79}{10}

z^{2} - 2 z + 1 = 0

6 x - 6 x^{2} = 0

9 x^{2} - 12 x + 12 = 0

12 x^{2} - 240 x + 819 = 0

8 x^{2} - 12 x = 0

What are the solutions to the equation 3(x+1)-x(5x+2)=7 ?
The solutions to the equation 3(x+1)-x(5x+2)=7 are x= 1/10-i(sqrt(79))/(10),x= 1/10+i(sqrt(79))/(10)
Find the zeros of 3(x+1)-x(5x+2)=7
The zeros of 3(x+1)-x(5x+2)=7 are x= 1/10-i(sqrt(79))/(10),x= 1/10+i(sqrt(79))/(10)