What are the solutions to the equation y^2=8y ?

The solutions to the equation y^2=8y are y=8,y=0

Find the zeros of y^2=8y

The zeros of y^2=8y are y=8,y=0

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y^{2} = 8 y

y = 8, y = 0

Solution steps

y^{2} = 8 y

Move

8 y

to the left side

y^{2} - 8 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 0 = 8

y_{1, 2} = \frac{- ( - 8 ) \pm 8}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 8 ) + 8}{2 \cdot 1}, y_{2} = \frac{- ( - 8 ) - 8}{2 \cdot 1}

y = \frac{- ( - 8 ) + 8}{2 \cdot 1} : 8

y = \frac{- ( - 8 ) - 8}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

y = 8, y = 0

x, x^{2} + x y + y = x - 4

p^{2} - 2 p - 7 = 0

6 x^{2} - 42 x + 72 = 0

x^{2} + 24 x

3 x^{2} - b x + 1 = 0

What are the solutions to the equation y^2=8y ?
The solutions to the equation y^2=8y are y=8,y=0
Find the zeros of y^2=8y
The zeros of y^2=8y are y=8,y=0