What are the solutions to the equation x(3x-6)-4+9(x-1)=5 ?

The solutions to the equation x(3x-6)-4+9(x-1)=5 are x=2,x=-3

Find the zeros of x(3x-6)-4+9(x-1)=5

The zeros of x(3x-6)-4+9(x-1)=5 are x=2,x=-3

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x (3 x - 6) - 4 + 9 (x - 1) = 5

x = 2, x = - 3

Solution steps

x (3 x - 6) - 4 + 9 (x - 1) = 5

Expand

x (3 x - 6) - 4 + 9 (x - 1) : 3 x^{2} + 3 x - 13

3 x^{2} + 3 x - 13 = 5

Move

5

to the left side

3 x^{2} + 3 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 3 ( - 18 )}{2 \cdot 3}

3^{2} - 4 \cdot 3 (- 18) = 15

x_{1, 2} = \frac{- 3 \pm 15}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 3 + 15}{2 \cdot 3}, x_{2} = \frac{- 3 - 15}{2 \cdot 3}

x = \frac{- 3 + 15}{2 \cdot 3} : 2

x = \frac{- 3 - 15}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

x = 2, x = - 3

x^{2} - 10 x + 25 = 0

5 d^{2} + 6 d + 1 = 4 d^{2}

3 x^{2} - 4 = 140

3 x^{2} - 10 = 38

x, x^{2} + y^{2} - 2 x + 2 y + 2 = 0

What are the solutions to the equation x(3x-6)-4+9(x-1)=5 ?
The solutions to the equation x(3x-6)-4+9(x-1)=5 are x=2,x=-3
Find the zeros of x(3x-6)-4+9(x-1)=5
The zeros of x(3x-6)-4+9(x-1)=5 are x=2,x=-3