What are the solutions to the equation 3x^2+bx+3=0 ?

The solutions to the equation 3x^2+bx+3=0 are x=(-b+sqrt(b^2-36))/6 ,x=(-b-sqrt(b^2-36))/6

Find the zeros of 3x^2+bx+3=0

The zeros of 3x^2+bx+3=0 are x=(-b+sqrt(b^2-36))/6 ,x=(-b-sqrt(b^2-36))/6

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3 x^{2} + b x + 3 = 0

x = \frac{- b + b ^{2} - 36}{6}, x = \frac{- b - b ^{2} - 36}{6}

Solution steps

3 x^{2} + b x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- b \pm b ^{2} - 4 \cdot 3 \cdot 3}{2 \cdot 3}

Simplify

b^{2} - 4 \cdot 3 \cdot 3 : b^{2} - 36

x_{1, 2} = \frac{- b \pm b ^{2} - 36}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- b + b ^{2} - 36}{2 \cdot 3}, x_{2} = \frac{- b - b ^{2} - 36}{2 \cdot 3}

x = \frac{- b + b ^{2} - 36}{2 \cdot 3} : \frac{- b + b ^{2} - 36}{6}

x = \frac{- b - b ^{2} - 36}{2 \cdot 3} : \frac{- b - b ^{2} - 36}{6}

The solutions to the quadratic equation are:

x = \frac{- b + b ^{2} - 36}{6}, x = \frac{- b - b ^{2} - 36}{6}

- 3 x^{2} - 18 x + 81 = 0

- 101 = - 3 x^{2} - 5

x (1 - 3 x) = 2 x - 1

2 x^{2} - 9 x - 13 = - 8

10 x^{2} + 15 = 0

What are the solutions to the equation 3x^2+bx+3=0 ?
The solutions to the equation 3x^2+bx+3=0 are x=(-b+sqrt(b^2-36))/6 ,x=(-b-sqrt(b^2-36))/6
Find the zeros of 3x^2+bx+3=0
The zeros of 3x^2+bx+3=0 are x=(-b+sqrt(b^2-36))/6 ,x=(-b-sqrt(b^2-36))/6