What are the solutions to the equation 9x^2+38=36x ?

The solutions to the equation 9x^2+38=36x are x=2+i(sqrt(2))/3 ,x=2-i(sqrt(2))/3

Find the zeros of 9x^2+38=36x

The zeros of 9x^2+38=36x are x=2+i(sqrt(2))/3 ,x=2-i(sqrt(2))/3

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9 x^{2} + 38 = 36 x

x = 2 + i \frac{2}{3}, x = 2 - i \frac{2}{3}

Solution steps

9 x^{2} + 38 = 36 x

Move

36 x

to the left side

9 x^{2} + 38 - 36 x = 0

Write in the standard form

a x^{2} + b x + c = 0

9 x^{2} - 36 x + 38 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 9 \cdot 38}{2 \cdot 9}

Simplify

(- 36)^{2} - 4 \cdot 9 \cdot 38 : 62 i

x_{1, 2} = \frac{- ( - 36 ) \pm 6 2 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 6 2 i}{2 \cdot 9}, x_{2} = \frac{- ( - 36 ) - 6 2 i}{2 \cdot 9}

x = \frac{- ( - 36 ) + 6 2 i}{2 \cdot 9} : 2 + i \frac{2}{3}

x = \frac{- ( - 36 ) - 6 2 i}{2 \cdot 9} : 2 - i \frac{2}{3}

The solutions to the quadratic equation are:

x = 2 + i \frac{2}{3}, x = 2 - i \frac{2}{3}

x^{2} - 16 x + 64 = 64

7 x^{2} - 9 x + 2 = 0

- 4 x^{2} - 5 x + 1 = 0

7 x^{2} - (2 x - 3)^{2} = 3 (4 x + 1)

12 x^{2} - 80 x + 100 = 0

What are the solutions to the equation 9x^2+38=36x ?
The solutions to the equation 9x^2+38=36x are x=2+i(sqrt(2))/3 ,x=2-i(sqrt(2))/3
Find the zeros of 9x^2+38=36x
The zeros of 9x^2+38=36x are x=2+i(sqrt(2))/3 ,x=2-i(sqrt(2))/3