What are the solutions to the equation solvefor x,x^2+y^2=1 ?

The solutions to the equation solvefor x,x^2+y^2=1 are x=sqrt(1-y^2),x=-sqrt(1-y^2)

Find the zeros of solvefor x,x^2+y^2=1

The zeros of solvefor x,x^2+y^2=1 are x=sqrt(1-y^2),x=-sqrt(1-y^2)

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solve for

x, x^{2} + y^{2} = 1

x = 1 - y^{2}, x = - 1 - y^{2}

Solution steps

x^{2} + y^{2} = 1

Move

y^{2}

to the right side

x^{2} = 1 - y^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1 - y^{2}, x = - 1 - y^{2}

4 x^{2} - 40 x - 12 = 0

- 2 x^{2} - 4 x = 0

3 x^{2} - 5 x - 3 = 0

x, x^{2} + y^{2} - 4 x - 6 y + 13 = 0

5 x^{2} + x - 20 = 0

What are the solutions to the equation solvefor x,x^2+y^2=1 ?
The solutions to the equation solvefor x,x^2+y^2=1 are x=sqrt(1-y^2),x=-sqrt(1-y^2)
Find the zeros of solvefor x,x^2+y^2=1
The zeros of solvefor x,x^2+y^2=1 are x=sqrt(1-y^2),x=-sqrt(1-y^2)