What are the solutions to the equation x^2-16x-36=0 ?

The solutions to the equation x^2-16x-36=0 are x=18,x=-2

Find the zeros of x^2-16x-36=0

The zeros of x^2-16x-36=0 are x=18,x=-2

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x^{2} - 16 x - 36 = 0

x = 18, x = - 2

Solution steps

x^{2} - 16 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot (- 36) = 20

x_{1, 2} = \frac{- ( - 16 ) \pm 20}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 20}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 20}{2 \cdot 1}

x = \frac{- ( - 16 ) + 20}{2 \cdot 1} : 18

x = \frac{- ( - 16 ) - 20}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 18, x = - 2

3 x^{2} - 6 x - 5

3 x^{2} + 2 x = - 7

x^{2} - 6 x + 5

x^{2} + 7 x + 36 = 0

- 6 x^{2} - 24 x - 240 = 0

What are the solutions to the equation x^2-16x-36=0 ?
The solutions to the equation x^2-16x-36=0 are x=18,x=-2
Find the zeros of x^2-16x-36=0
The zeros of x^2-16x-36=0 are x=18,x=-2