What are the solutions to the equation 2z^2+2z-1=0 ?

The solutions to the equation 2z^2+2z-1=0 are z=(-1+sqrt(3))/2 ,z=-(1+sqrt(3))/2

Find the zeros of 2z^2+2z-1=0

The zeros of 2z^2+2z-1=0 are z=(-1+sqrt(3))/2 ,z=-(1+sqrt(3))/2

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2 z^{2} + 2 z - 1 = 0

z = \frac{- 1 + 3}{2}, z = - \frac{1 + 3}{2}

Decimal Notation

z = 0.36602 \dots, z = - 1.36602 \dots

Solution steps

2 z^{2} + 2 z - 1 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

2^{2} - 4 \cdot 2 (- 1) = 23

z_{1, 2} = \frac{- 2 \pm 2 3}{2 \cdot 2}

Separate the solutions

z_{1} = \frac{- 2 + 2 3}{2 \cdot 2}, z_{2} = \frac{- 2 - 2 3}{2 \cdot 2}

z = \frac{- 2 + 2 3}{2 \cdot 2} : \frac{- 1 + 3}{2}

z = \frac{- 2 - 2 3}{2 \cdot 2} : - \frac{1 + 3}{2}

The solutions to the quadratic equation are:

z = \frac{- 1 + 3}{2}, z = - \frac{1 + 3}{2}

(x + 2)^{3} - (x - 1)^{3} = x (3 x + 4) + 8

x^{2} + (x + 3)^{2} = 1 5^{2}

(6 + 2 x) (10 + 2 x) - 60 = 36

3 a x^{2} + 2 b x + c = 0

x^{2} + 12 x + 10 = 0

What are the solutions to the equation 2z^2+2z-1=0 ?
The solutions to the equation 2z^2+2z-1=0 are z=(-1+sqrt(3))/2 ,z=-(1+sqrt(3))/2
Find the zeros of 2z^2+2z-1=0
The zeros of 2z^2+2z-1=0 are z=(-1+sqrt(3))/2 ,z=-(1+sqrt(3))/2