What are the solutions to the equation x^2+10x-25=4x+2 ?

The solutions to the equation x^2+10x-25=4x+2 are x=3,x=-9

Find the zeros of x^2+10x-25=4x+2

The zeros of x^2+10x-25=4x+2 are x=3,x=-9

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x^{2} + 10 x - 25 = 4 x + 2

x = 3, x = - 9

Solution steps

x^{2} + 10 x - 25 = 4 x + 2

Move

2

to the left side

x^{2} + 10 x - 27 = 4 x

Move

4 x

to the left side

x^{2} + 6 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 27 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 27) = 12

x_{1, 2} = \frac{- 6 \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 12}{2 \cdot 1}, x_{2} = \frac{- 6 - 12}{2 \cdot 1}

x = \frac{- 6 + 12}{2 \cdot 1} : 3

x = \frac{- 6 - 12}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 3, x = - 9

s^{2} + s + 1

5 x^{2} - 36 x + 36 = 0

(x + 3) (x - 6) = 0

x^{2} + 3 x - 5

- 2 x^{2} + 20 x - 68 = 0

What are the solutions to the equation x^2+10x-25=4x+2 ?
The solutions to the equation x^2+10x-25=4x+2 are x=3,x=-9
Find the zeros of x^2+10x-25=4x+2
The zeros of x^2+10x-25=4x+2 are x=3,x=-9