What are the solutions to the equation s^2+2=0 ?

The solutions to the equation s^2+2=0 are s=sqrt(2)i,s=-sqrt(2)i

Find the zeros of s^2+2=0

The zeros of s^2+2=0 are s=sqrt(2)i,s=-sqrt(2)i

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s^{2} + 2 = 0

s = 2 i, s = - 2 i

Solution steps

s^{2} + 2 = 0

Move

2

to the right side

s^{2} = - 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

s = - 2, s = - - 2

- 2 = 2 i

- - 2 = - 2 i

s = 2 i, s = - 2 i

8 x^{2} - 11 x = - 3

5 (5 x + 2)^{2} - 15 = 30

(2 x - 3)^{2} = 16

z^{2} + 9 = 0

135 = (2 x + 3) (2 x - 3)

What are the solutions to the equation s^2+2=0 ?
The solutions to the equation s^2+2=0 are s=sqrt(2)i,s=-sqrt(2)i
Find the zeros of s^2+2=0
The zeros of s^2+2=0 are s=sqrt(2)i,s=-sqrt(2)i