What are the solutions to the equation w^2-4w-77=0 ?

The solutions to the equation w^2-4w-77=0 are w=11,w=-7

Find the zeros of w^2-4w-77=0

The zeros of w^2-4w-77=0 are w=11,w=-7

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w^{2} - 4 w - 77 = 0

w = 11, w = - 7

Solution steps

w^{2} - 4 w - 77 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 77 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 77) = 18

w_{1, 2} = \frac{- ( - 4 ) \pm 18}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 4 ) + 18}{2 \cdot 1}, w_{2} = \frac{- ( - 4 ) - 18}{2 \cdot 1}

w = \frac{- ( - 4 ) + 18}{2 \cdot 1} : 11

w = \frac{- ( - 4 ) - 18}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

w = 11, w = - 7

9 x^{2} + 16 = 24 x

n^{2} - n - 5 = - 2 n^{2}

n^{2} - 5 n + 6 = 0

x^{2} - 64 x = - 1.24

5 x^{2} - 22 x + 11 = 3

What are the solutions to the equation w^2-4w-77=0 ?
The solutions to the equation w^2-4w-77=0 are w=11,w=-7
Find the zeros of w^2-4w-77=0
The zeros of w^2-4w-77=0 are w=11,w=-7