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What are the solutions to the equation -16(x)^2+40(x)+3=0 ?
The solutions to the equation -16(x)^2+40(x)+3=0 are x=-(-5+2sqrt(7))/4 ,x=(5+2sqrt(7))/4Find the zeros of -16(x)^2+40(x)+3=0
The zeros of -16(x)^2+40(x)+3=0 are x=-(-5+2sqrt(7))/4 ,x=(5+2sqrt(7))/4