What are the solutions to the equation 3(2w-3)^2-5=70 ?

The solutions to the equation 3(2w-3)^2-5=70 are w=4,w=-1

Find the zeros of 3(2w-3)^2-5=70

The zeros of 3(2w-3)^2-5=70 are w=4,w=-1

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3 (2 w - 3)^{2} - 5 = 70

w = 4, w = - 1

Solution steps

3 (2 w - 3)^{2} - 5 = 70

Move

5

to the right side

3 (2 w - 3)^{2} = 75

Divide both sides by

3

(2 w - 3)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 w - 3 = 25 : w = 4

Solve

2 w - 3 = - 25 : w = - 1

The solutions to the quadratic equation are:

w = 4, w = - 1

x^{2} - 2 x = - x^{2} + 4 x

t, f (t - 3) = - (t - 3)^{2} + 6 (t - 3) - 11

8 x^{2} + 128 = 0

y, x^{2} + y^{2} = 25

x^{2} + 10 x + 25 = 36

What are the solutions to the equation 3(2w-3)^2-5=70 ?
The solutions to the equation 3(2w-3)^2-5=70 are w=4,w=-1
Find the zeros of 3(2w-3)^2-5=70
The zeros of 3(2w-3)^2-5=70 are w=4,w=-1