What are the solutions to the equation x^2-9x-580=0 ?

The solutions to the equation x^2-9x-580=0 are x=29,x=-20

Find the zeros of x^2-9x-580=0

The zeros of x^2-9x-580=0 are x=29,x=-20

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x^{2} - 9 x - 580 = 0

x = 29, x = - 20

Solution steps

x^{2} - 9 x - 580 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot ( - 580 )}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot (- 580) = 49

x_{1, 2} = \frac{- ( - 9 ) \pm 49}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 49}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 49}{2 \cdot 1}

x = \frac{- ( - 9 ) + 49}{2 \cdot 1} : 29

x = \frac{- ( - 9 ) - 49}{2 \cdot 1} : - 20

The solutions to the quadratic equation are:

x = 29, x = - 20

25 (x^{2} + 1) - 13 = 13

x^{2} + 5 x + 4 = 0

1 3^{2} = x^{2} + 5^{2}

x^{2} + \frac{9}{25} = \frac{6}{5} x

6 x^{2} + 72 = 0

What are the solutions to the equation x^2-9x-580=0 ?
The solutions to the equation x^2-9x-580=0 are x=29,x=-20
Find the zeros of x^2-9x-580=0
The zeros of x^2-9x-580=0 are x=29,x=-20