What are the solutions to the equation solvefor x,x^2+y^2=2xy ?

The solutions to the equation solvefor x,x^2+y^2=2xy are x=y

Find the zeros of solvefor x,x^2+y^2=2xy

The zeros of solvefor x,x^2+y^2=2xy are x=y

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solve for

x, x^{2} + y^{2} = 2 x y

x = y

Solution steps

x^{2} + y^{2} = 2 x y

Move

2 x y

to the left side

x^{2} + y^{2} - 2 x y = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 2 y x + y^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 y ) \pm ( - 2 y ) ^{2} - 4 \cdot 1 \cdot y ^{2}}{2 \cdot 1}

(- 2 y)^{2} - 4 \cdot 1 \cdot y^{2} = 0

x_{1, 2} = \frac{- ( - 2 y ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 2 y )}{2 \cdot 1}

Simplify

\frac{- ( - 2 y )}{2 \cdot 1} : y

x = y

The solution to the quadratic equation is:

x = y

a^{2} + 5 a - 8 = 0

x^{2} = 2

x^{2} + 14 x - 5 = 0

(3 x - 4) (x + 1) = - 2

30 x^{2} - 47 x + 14 = 0

What are the solutions to the equation solvefor x,x^2+y^2=2xy ?
The solutions to the equation solvefor x,x^2+y^2=2xy are x=y
Find the zeros of solvefor x,x^2+y^2=2xy
The zeros of solvefor x,x^2+y^2=2xy are x=y