What are the solutions to the equation 2x^2-7x-13=0 ?

The solutions to the equation 2x^2-7x-13=0 are x=(7+3sqrt(17))/4 ,x=(7-3sqrt(17))/4

Find the zeros of 2x^2-7x-13=0

The zeros of 2x^2-7x-13=0 are x=(7+3sqrt(17))/4 ,x=(7-3sqrt(17))/4

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2 x^{2} - 7 x - 13 = 0

x = \frac{7 + 3 17}{4}, x = \frac{7 - 3 17}{4}

Decimal Notation

x = 4.84232 \dots, x = - 1.34232 \dots

Solution steps

2 x^{2} - 7 x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 ( - 13 )}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 (- 13) = 317

x_{1, 2} = \frac{- ( - 7 ) \pm 3 17}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 3 17}{2 \cdot 2}, x_{2} = \frac{- ( - 7 ) - 3 17}{2 \cdot 2}

x = \frac{- ( - 7 ) + 3 17}{2 \cdot 2} : \frac{7 + 3 17}{4}

x = \frac{- ( - 7 ) - 3 17}{2 \cdot 2} : \frac{7 - 3 17}{4}

The solutions to the quadratic equation are:

x = \frac{7 + 3 17}{4}, x = \frac{7 - 3 17}{4}

x^{2} - 3 x + 9

x^{2} + 15 x - 16 = 0

2 x^{2} - 9 x - 4 = 0

4 x^{2} + 16 x - 1

2 x^{2} + 10 = 4 x + 16

What are the solutions to the equation 2x^2-7x-13=0 ?
The solutions to the equation 2x^2-7x-13=0 are x=(7+3sqrt(17))/4 ,x=(7-3sqrt(17))/4
Find the zeros of 2x^2-7x-13=0
The zeros of 2x^2-7x-13=0 are x=(7+3sqrt(17))/4 ,x=(7-3sqrt(17))/4