What are the solutions to the equation r^2-4r=0 ?

The solutions to the equation r^2-4r=0 are r=4,r=0

Find the zeros of r^2-4r=0

The zeros of r^2-4r=0 are r=4,r=0

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r^{2} - 4 r = 0

r = 4, r = 0

Solution steps

r^{2} - 4 r = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 0 = 4

r_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 1}, r_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 1}

r = \frac{- ( - 4 ) + 4}{2 \cdot 1} : 4

r = \frac{- ( - 4 ) - 4}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

r = 4, r = 0

- x^{2} - 2 x + 3

5 - 6 x - x^{2}

(2 x + 3)^{2} = 36

(2 x + 3)^{2} = 20

x^{2} + 12 x + 8 = 0

What are the solutions to the equation r^2-4r=0 ?
The solutions to the equation r^2-4r=0 are r=4,r=0
Find the zeros of r^2-4r=0
The zeros of r^2-4r=0 are r=4,r=0