What are the solutions to the equation d^2+20=-300 ?

The solutions to the equation d^2+20=-300 are d=8sqrt(5)i,d=-8sqrt(5)i

Find the zeros of d^2+20=-300

The zeros of d^2+20=-300 are d=8sqrt(5)i,d=-8sqrt(5)i

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d^{2} + 20 = - 300

d = 85 i, d = - 85 i

Solution steps

d^{2} + 20 = - 300

Move

20

to the right side

d^{2} = - 320

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

d = - 320, d = - - 320

- 320 = 85 i

- - 320 = - 85 i

d = 85 i, d = - 85 i

- 5 (3 x^{2} + 5 x + b) = a x^{2} - 25 x + 45

x^{2} + 10 x - 56 = 0

2 x^{2} = - 5 x + 3

(x - 2) (x + 1) = 0

4 x^{2} - 40 x - 96 = 0

What are the solutions to the equation d^2+20=-300 ?
The solutions to the equation d^2+20=-300 are d=8sqrt(5)i,d=-8sqrt(5)i
Find the zeros of d^2+20=-300
The zeros of d^2+20=-300 are d=8sqrt(5)i,d=-8sqrt(5)i