What are the solutions to the equation 12x^2-520x+4000=0 ?

The solutions to the equation 12x^2-520x+4000=0 are x= 100/3 ,x=10

Find the zeros of 12x^2-520x+4000=0

The zeros of 12x^2-520x+4000=0 are x= 100/3 ,x=10

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12 x^{2} - 520 x + 4000 = 0

x = \frac{100}{3}, x = 10

Decimal Notation

x = 33.33333 \dots, x = 10

Solution steps

12 x^{2} - 520 x + 4000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 520 ) \pm ( - 520 ) ^{2} - 4 \cdot 12 \cdot 4000}{2 \cdot 12}

(- 520)^{2} - 4 \cdot 12 \cdot 4000 = 280

x_{1, 2} = \frac{- ( - 520 ) \pm 280}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 520 ) + 280}{2 \cdot 12}, x_{2} = \frac{- ( - 520 ) - 280}{2 \cdot 12}

x = \frac{- ( - 520 ) + 280}{2 \cdot 12} : \frac{100}{3}

x = \frac{- ( - 520 ) - 280}{2 \cdot 12} : 10

The solutions to the quadratic equation are:

x = \frac{100}{3}, x = 10

x = 5 x^{2}

(x + 2)^{2} = 64

a^{2} = 9

v^{2} - v = 72

x^{2} = 2 x + 99

What are the solutions to the equation 12x^2-520x+4000=0 ?
The solutions to the equation 12x^2-520x+4000=0 are x= 100/3 ,x=10
Find the zeros of 12x^2-520x+4000=0
The zeros of 12x^2-520x+4000=0 are x= 100/3 ,x=10