What are the solutions to the equation 2x^2=12 ?

The solutions to the equation 2x^2=12 are x=sqrt(6),x=-sqrt(6)

Find the zeros of 2x^2=12

The zeros of 2x^2=12 are x=sqrt(6),x=-sqrt(6)

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2 x^{2} = 12

x = 6, x = - 6

Decimal Notation

x = 2.44948 \dots, x = - 2.44948 \dots

Solution steps

2 x^{2} = 12

Divide both sides by

2

x^{2} = 6

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 6, x = - 6

m \frac{m - 3}{4} + \frac{m + 4}{3} = - 7

(x - 3) (x - 4) = 0

3 x^{2} + 14 x = 5

5 t^{2} - 8 t + 3 = 2 t

- x^{2} - 6 x - 11 = 0

What are the solutions to the equation 2x^2=12 ?
The solutions to the equation 2x^2=12 are x=sqrt(6),x=-sqrt(6)
Find the zeros of 2x^2=12
The zeros of 2x^2=12 are x=sqrt(6),x=-sqrt(6)