What are the solutions to the equation 4(2x-3)^2+14=34 ?

The solutions to the equation 4(2x-3)^2+14=34 are x=(sqrt(5)+3)/2 ,x=(-sqrt(5)+3)/2

Find the zeros of 4(2x-3)^2+14=34

The zeros of 4(2x-3)^2+14=34 are x=(sqrt(5)+3)/2 ,x=(-sqrt(5)+3)/2

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4 (2 x - 3)^{2} + 14 = 34

x = \frac{5 + 3}{2}, x = \frac{- 5 + 3}{2}

Decimal Notation

x = 2.61803 \dots, x = 0.38196 \dots

Solution steps

4 (2 x - 3)^{2} + 14 = 34

Move

14

to the right side

4 (2 x - 3)^{2} = 20

Divide both sides by

4

(2 x - 3)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 3 = 5 : x = \frac{5 + 3}{2}

Solve

2 x - 3 = - 5 : x = \frac{- 5 + 3}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 3}{2}, x = \frac{- 5 + 3}{2}

c, 4 c^{2} θt = (θ^{2} - t^{2})^{2}

y^{2} + 5 y = 0

5 x^{2} + 12 x = 0

a, a (a - y) = b (y - b) - 2 ab

x^{2} - 2 x = 10

What are the solutions to the equation 4(2x-3)^2+14=34 ?
The solutions to the equation 4(2x-3)^2+14=34 are x=(sqrt(5)+3)/2 ,x=(-sqrt(5)+3)/2
Find the zeros of 4(2x-3)^2+14=34
The zeros of 4(2x-3)^2+14=34 are x=(sqrt(5)+3)/2 ,x=(-sqrt(5)+3)/2