What are the solutions to the equation (3x-4)(x+5)=0 ?

The solutions to the equation (3x-4)(x+5)=0 are x= 4/3 ,x=-5

Find the zeros of (3x-4)(x+5)=0

The zeros of (3x-4)(x+5)=0 are x= 4/3 ,x=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(3 x - 4) (x + 5) = 0

x = \frac{4}{3}, x = - 5

Decimal Notation

x = 1.33333 \dots, x = - 5

Solution steps

(3 x - 4) (x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 4 = 0 or x + 5 = 0

Solve

3 x - 4 = 0 : x = \frac{4}{3}

Solve

x + 5 = 0 : x = - 5

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - 5

x (x + 1) = 30

\frac{1}{3} x^{2} + \frac{5}{6} x = 0

10 x^{2} - 2 = 0

5 x^{2} - 17 x + 19 = 2 x^{2}

3 x^{2} - 30 x = 0

What are the solutions to the equation (3x-4)(x+5)=0 ?
The solutions to the equation (3x-4)(x+5)=0 are x= 4/3 ,x=-5
Find the zeros of (3x-4)(x+5)=0
The zeros of (3x-4)(x+5)=0 are x= 4/3 ,x=-5