What are the solutions to the equation 0=-4x^2+x+3 ?

The solutions to the equation 0=-4x^2+x+3 are x=-3/4 ,x=1

Find the zeros of 0=-4x^2+x+3

The zeros of 0=-4x^2+x+3 are x=-3/4 ,x=1

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0 = - 4 x^{2} + x + 3

x = - \frac{3}{4}, x = 1

Decimal Notation

x = - 0.75, x = 1

Solution steps

0 = - 4 x^{2} + x + 3

Switch sides

- 4 x^{2} + x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 4 ) \cdot 3}{2 ( - 4 )}

1^{2} - 4 (- 4) \cdot 3 = 7

x_{1, 2} = \frac{- 1 \pm 7}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 1 + 7}{2 ( - 4 )}, x_{2} = \frac{- 1 - 7}{2 ( - 4 )}

x = \frac{- 1 + 7}{2 ( - 4 )} : - \frac{3}{4}

x = \frac{- 1 - 7}{2 ( - 4 )} : 1

The solutions to the quadratic equation are:

x = - \frac{3}{4}, x = 1

(5 h^{3} - 8 h) + (- 2 h^{3} - h^{2} - 2 h)

- 24 + 7 x < 11

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\frac{8 i}{4 - 2 i}

lo g_{16} (256)

What are the solutions to the equation 0=-4x^2+x+3 ?
The solutions to the equation 0=-4x^2+x+3 are x=-3/4 ,x=1
Find the zeros of 0=-4x^2+x+3
The zeros of 0=-4x^2+x+3 are x=-3/4 ,x=1