What are the solutions to the equation 5v^2+17v+5=6v ?

The solutions to the equation 5v^2+17v+5=6v are v=(-11+sqrt(21))/(10),v=(-11-sqrt(21))/(10)

Find the zeros of 5v^2+17v+5=6v

The zeros of 5v^2+17v+5=6v are v=(-11+sqrt(21))/(10),v=(-11-sqrt(21))/(10)

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5 v^{2} + 17 v + 5 = 6 v

v = \frac{- 11 + 21}{10}, v = \frac{- 11 - 21}{10}

Decimal Notation

v = - 0.64174 \dots, v = - 1.55825 \dots

Solution steps

5 v^{2} + 17 v + 5 = 6 v

Move

6 v

to the left side

5 v^{2} + 11 v + 5 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 5 \cdot 5}{2 \cdot 5}

1 1^{2} - 4 \cdot 5 \cdot 5 = 21

v_{1, 2} = \frac{- 11 \pm 21}{2 \cdot 5}

Separate the solutions

v_{1} = \frac{- 11 + 21}{2 \cdot 5}, v_{2} = \frac{- 11 - 21}{2 \cdot 5}

v = \frac{- 11 + 21}{2 \cdot 5} : \frac{- 11 + 21}{10}

v = \frac{- 11 - 21}{2 \cdot 5} : \frac{- 11 - 21}{10}

The solutions to the quadratic equation are:

v = \frac{- 11 + 21}{10}, v = \frac{- 11 - 21}{10}

x^{2} = \frac{7}{3}

x^{2} - 3 x + 4 = 12

(5 x - 3) (2 x + 1) = 46 - x

4 x^{2} + 28 x + 53 = 0

\frac{x ^{2} + 2}{3} = \frac{2 x}{4}

What are the solutions to the equation 5v^2+17v+5=6v ?
The solutions to the equation 5v^2+17v+5=6v are v=(-11+sqrt(21))/(10),v=(-11-sqrt(21))/(10)
Find the zeros of 5v^2+17v+5=6v
The zeros of 5v^2+17v+5=6v are v=(-11+sqrt(21))/(10),v=(-11-sqrt(21))/(10)