What are the solutions to the equation 6x^2+x+1=0 ?

The solutions to the equation 6x^2+x+1=0 are x=-1/12+i(sqrt(23))/(12),x=-1/12-i(sqrt(23))/(12)

Find the zeros of 6x^2+x+1=0

The zeros of 6x^2+x+1=0 are x=-1/12+i(sqrt(23))/(12),x=-1/12-i(sqrt(23))/(12)

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6 x^{2} + x + 1 = 0

x = - \frac{1}{12} + i \frac{23}{12}, x = - \frac{1}{12} - i \frac{23}{12}

Solution steps

6 x^{2} + x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 6 \cdot 1}{2 \cdot 6}

Simplify

1^{2} - 4 \cdot 6 \cdot 1 : 23 i

x_{1, 2} = \frac{- 1 \pm 23 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 1 + 23 i}{2 \cdot 6}, x_{2} = \frac{- 1 - 23 i}{2 \cdot 6}

x = \frac{- 1 + 23 i}{2 \cdot 6} : - \frac{1}{12} + i \frac{23}{12}

x = \frac{- 1 - 23 i}{2 \cdot 6} : - \frac{1}{12} - i \frac{23}{12}

The solutions to the quadratic equation are:

x = - \frac{1}{12} + i \frac{23}{12}, x = - \frac{1}{12} - i \frac{23}{12}

2 k^{2} - 37 = 61

x^{2} - 7 = 9

y^{2} + 6 y

- 3 x^{2} + 297 = 0

2 x^{2} + 16 x - 7

What are the solutions to the equation 6x^2+x+1=0 ?
The solutions to the equation 6x^2+x+1=0 are x=-1/12+i(sqrt(23))/(12),x=-1/12-i(sqrt(23))/(12)
Find the zeros of 6x^2+x+1=0
The zeros of 6x^2+x+1=0 are x=-1/12+i(sqrt(23))/(12),x=-1/12-i(sqrt(23))/(12)