What are the solutions to the equation 2x^2-2x+6=0 ?

The solutions to the equation 2x^2-2x+6=0 are x= 1/2+i(sqrt(11))/2 ,x= 1/2-i(sqrt(11))/2

Find the zeros of 2x^2-2x+6=0

The zeros of 2x^2-2x+6=0 are x= 1/2+i(sqrt(11))/2 ,x= 1/2-i(sqrt(11))/2

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2 x^{2} - 2 x + 6 = 0

x = \frac{1}{2} + i \frac{11}{2}, x = \frac{1}{2} - i \frac{11}{2}

Solution steps

2 x^{2} - 2 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

Simplify

(- 2)^{2} - 4 \cdot 2 \cdot 6 : 211 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 11 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 11 i}{2 \cdot 2}, x_{2} = \frac{- ( - 2 ) - 2 11 i}{2 \cdot 2}

x = \frac{- ( - 2 ) + 2 11 i}{2 \cdot 2} : \frac{1}{2} + i \frac{11}{2}

x = \frac{- ( - 2 ) - 2 11 i}{2 \cdot 2} : \frac{1}{2} - i \frac{11}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{11}{2}, x = \frac{1}{2} - i \frac{11}{2}

θ^{2} + 54 = 90

x^{2} - 2 x - 62 = x + 8

m^{2} - 3 m - 4 = 0

3 x^{2} + 12 x - 21 = 0

x^{2} + x - 11 = 0

What are the solutions to the equation 2x^2-2x+6=0 ?
The solutions to the equation 2x^2-2x+6=0 are x= 1/2+i(sqrt(11))/2 ,x= 1/2-i(sqrt(11))/2
Find the zeros of 2x^2-2x+6=0
The zeros of 2x^2-2x+6=0 are x= 1/2+i(sqrt(11))/2 ,x= 1/2-i(sqrt(11))/2