What are the solutions to the equation 4x^2-12x+9=9 ?

The solutions to the equation 4x^2-12x+9=9 are x=3,x=0

Find the zeros of 4x^2-12x+9=9

The zeros of 4x^2-12x+9=9 are x=3,x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} - 12 x + 9 = 9

x = 3, x = 0

Solution steps

4 x^{2} - 12 x + 9 = 9

Move

9

to the left side

4 x^{2} - 12 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 \cdot 0 = 12

x_{1, 2} = \frac{- ( - 12 ) \pm 12}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 12}{2 \cdot 4}, x_{2} = \frac{- ( - 12 ) - 12}{2 \cdot 4}

x = \frac{- ( - 12 ) + 12}{2 \cdot 4} : 3

x = \frac{- ( - 12 ) - 12}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

x = 3, x = 0

12 x^{2} - 2 x - 4 = 0

2 x^{2} - 2 x - 15 = 0

x^{2} + 2 x + 1 = 15

x^{2} + 15 = 5 x

(x - 5) (x + 3) = 9

What are the solutions to the equation 4x^2-12x+9=9 ?
The solutions to the equation 4x^2-12x+9=9 are x=3,x=0
Find the zeros of 4x^2-12x+9=9
The zeros of 4x^2-12x+9=9 are x=3,x=0