What are the solutions to the equation 8x^2-7x-1=0 ?

The solutions to the equation 8x^2-7x-1=0 are x=1,x=-1/8

Find the zeros of 8x^2-7x-1=0

The zeros of 8x^2-7x-1=0 are x=1,x=-1/8

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8 x^{2} - 7 x - 1 = 0

x = 1, x = - \frac{1}{8}

Decimal

x = 1, x = - 0.125

Solution steps

8 x^{2} - 7 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 8 ( - 1 )}{2 \cdot 8}

(- 7)^{2} - 4 \cdot 8 (- 1) = 9

x_{1, 2} = \frac{- ( - 7 ) \pm 9}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 9}{2 \cdot 8}, x_{2} = \frac{- ( - 7 ) - 9}{2 \cdot 8}

x = \frac{- ( - 7 ) + 9}{2 \cdot 8} : 1

x = \frac{- ( - 7 ) - 9}{2 \cdot 8} : - \frac{1}{8}

The solutions to the quadratic equation are:

x = 1, x = - \frac{1}{8}

8 m^{2} - 6 m - 9 = 0

\frac{2 π}{π}

x^{8} - 17 x^{4} + 16

(4 + 5 i) (4 - 5 i)

- \frac{π}{4} + \frac{π}{2}

What are the solutions to the equation 8x^2-7x-1=0 ?
The solutions to the equation 8x^2-7x-1=0 are x=1,x=-1/8
Find the zeros of 8x^2-7x-1=0
The zeros of 8x^2-7x-1=0 are x=1,x=-1/8