What are the solutions to the equation 9x^2+10=12x ?

The solutions to the equation 9x^2+10=12x are x= 2/3+isqrt(2/3),x= 2/3-isqrt(2/3)

Find the zeros of 9x^2+10=12x

The zeros of 9x^2+10=12x are x= 2/3+isqrt(2/3),x= 2/3-isqrt(2/3)

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9 x^{2} + 10 = 12 x

x = \frac{2}{3} + i \frac{2}{3}, x = \frac{2}{3} - i \frac{2}{3}

Solution steps

9 x^{2} + 10 = 12 x

Move

12 x

to the left side

9 x^{2} + 10 - 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

9 x^{2} - 12 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 9 \cdot 10}{2 \cdot 9}

Simplify

(- 12)^{2} - 4 \cdot 9 \cdot 10 : 66 i

x_{1, 2} = \frac{- ( - 12 ) \pm 6 6 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 6 6 i}{2 \cdot 9}, x_{2} = \frac{- ( - 12 ) - 6 6 i}{2 \cdot 9}

x = \frac{- ( - 12 ) + 6 6 i}{2 \cdot 9} : \frac{2}{3} + i \frac{2}{3}

x = \frac{- ( - 12 ) - 6 6 i}{2 \cdot 9} : \frac{2}{3} - i \frac{2}{3}

The solutions to the quadratic equation are:

x = \frac{2}{3} + i \frac{2}{3}, x = \frac{2}{3} - i \frac{2}{3}

x^{2} - 18 x - 2 = 0

2 x^{2} - 12 x + 23

v, m g h = \frac{1}{2} m v^{2}

9 x - 2 = - 5 x^{2}

a x^{2} + 6 x + c = 0

What are the solutions to the equation 9x^2+10=12x ?
The solutions to the equation 9x^2+10=12x are x= 2/3+isqrt(2/3),x= 2/3-isqrt(2/3)
Find the zeros of 9x^2+10=12x
The zeros of 9x^2+10=12x are x= 2/3+isqrt(2/3),x= 2/3-isqrt(2/3)