What are the solutions to the equation (x-4)^2=7 ?

The solutions to the equation (x-4)^2=7 are x=sqrt(7)+4,x=-sqrt(7)+4

Find the zeros of (x-4)^2=7

The zeros of (x-4)^2=7 are x=sqrt(7)+4,x=-sqrt(7)+4

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(x - 4)^{2} = 7

x = 7 + 4, x = - 7 + 4

Decimal Notation

x = 6.64575 \dots, x = 1.35424 \dots

Solution steps

(x - 4)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 7 : x = 7 + 4

Solve

x - 4 = - 7 : x = - 7 + 4

The solutions to the quadratic equation are:

x = 7 + 4, x = - 7 + 4

(2 x - 3)^{2} = 0

\frac{( X + 3 ) ^{2}}{16} - \frac{( X - 7 ) ^{2}}{4} = 1

2 x^{2} + 32 x + 272 = 0

2 x^{2} - 12 x + 26 = 0

x^{2} + 6 x + 8

What are the solutions to the equation (x-4)^2=7 ?
The solutions to the equation (x-4)^2=7 are x=sqrt(7)+4,x=-sqrt(7)+4
Find the zeros of (x-4)^2=7
The zeros of (x-4)^2=7 are x=sqrt(7)+4,x=-sqrt(7)+4