What are the solutions to the equation 3m^2-17m+15=-m ?

The solutions to the equation 3m^2-17m+15=-m are m=(8+sqrt(19))/3 ,m=(8-sqrt(19))/3

Find the zeros of 3m^2-17m+15=-m

The zeros of 3m^2-17m+15=-m are m=(8+sqrt(19))/3 ,m=(8-sqrt(19))/3

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3 m^{2} - 17 m + 15 = - m

m = \frac{8 + 19}{3}, m = \frac{8 - 19}{3}

Decimal Notation

m = 4.11963 \dots, m = 1.21370 \dots

Solution steps

3 m^{2} - 17 m + 15 = - m

Move

m

to the left side

3 m^{2} - 16 m + 15 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 3 \cdot 15}{2 \cdot 3}

(- 16)^{2} - 4 \cdot 3 \cdot 15 = 219

m_{1, 2} = \frac{- ( - 16 ) \pm 2 19}{2 \cdot 3}

Separate the solutions

m_{1} = \frac{- ( - 16 ) + 2 19}{2 \cdot 3}, m_{2} = \frac{- ( - 16 ) - 2 19}{2 \cdot 3}

m = \frac{- ( - 16 ) + 2 19}{2 \cdot 3} : \frac{8 + 19}{3}

m = \frac{- ( - 16 ) - 2 19}{2 \cdot 3} : \frac{8 - 19}{3}

The solutions to the quadratic equation are:

m = \frac{8 + 19}{3}, m = \frac{8 - 19}{3}

r, V = \frac{π r ^{2} h}{3}

- 3 (x + 6)^{2} - 7 = 0

x^{2} - 2 x + 0 = 0

3 x (2 x - 5) = - 4 x - 3

12 x^{2} + 6 x - 18 = 0

What are the solutions to the equation 3m^2-17m+15=-m ?
The solutions to the equation 3m^2-17m+15=-m are m=(8+sqrt(19))/3 ,m=(8-sqrt(19))/3
Find the zeros of 3m^2-17m+15=-m
The zeros of 3m^2-17m+15=-m are m=(8+sqrt(19))/3 ,m=(8-sqrt(19))/3