What are the solutions to the equation 20x^2+25x+5=0 ?

The solutions to the equation 20x^2+25x+5=0 are x=-1/4 ,x=-1

Find the zeros of 20x^2+25x+5=0

The zeros of 20x^2+25x+5=0 are x=-1/4 ,x=-1

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20 x^{2} + 25 x + 5 = 0

x = - \frac{1}{4}, x = - 1

Decimal Notation

x = - 0.25, x = - 1

Solution steps

20 x^{2} + 25 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 25 \pm 2 5 ^{2} - 4 \cdot 20 \cdot 5}{2 \cdot 20}

2 5^{2} - 4 \cdot 20 \cdot 5 = 15

x_{1, 2} = \frac{- 25 \pm 15}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- 25 + 15}{2 \cdot 20}, x_{2} = \frac{- 25 - 15}{2 \cdot 20}

x = \frac{- 25 + 15}{2 \cdot 20} : - \frac{1}{4}

x = \frac{- 25 - 15}{2 \cdot 20} : - 1

The solutions to the quadratic equation are:

x = - \frac{1}{4}, x = - 1

(x + 1) (x - 3) = - 3

c, a = b + c^{2} d

x, x^{2} + 4 y^{2} = 0

n^{2} + 6 n - 16 = 0

x^{2} + \frac{3}{4} x - 1

What are the solutions to the equation 20x^2+25x+5=0 ?
The solutions to the equation 20x^2+25x+5=0 are x=-1/4 ,x=-1
Find the zeros of 20x^2+25x+5=0
The zeros of 20x^2+25x+5=0 are x=-1/4 ,x=-1